Skip to Main Content
BECENational Examinations Council (NECO), NigeriaCertificationJunior Secondary Exit ExaminationPaper-Based

BECE Mathematics Numerical Literacy Practice Questions & Answers

Module: Numerical Literacy

Focus: Foundational Mathematics | Level: Junior Secondary (JSS3)

Comprehensive practice for the arithmetic and numeration section of the BECE Mathematics exam.

Key Topics:

  • Number & Numeration: Indices, fractions, decimals, and percentages.
  • Whole Numbers: Calculation involving large numbers and factors.
  • Basic Operations: Order of operations (BODMAS) and estimation.
  • Financial Math: Simple interest, profit and loss, and discount calculations.

Ready to test yourself?

Take this exam in our timed interactive simulator to track your performance and get detailed analytics.

What is the place value of the digit 7 in the number 24,789,105?

  • Hundred thousands

  • Ten thousands

  • Hundreds

  • Millions

View Answer & Explanation
Correct Answer: Option A -

Hundred thousands

Explanation:

In 24,789,105, the digit 7 is in the hundred thousands place (700,000700,000700,000).

Express the number three billion, two hundred and five million in figures.

  • 3,205,000,000

  • 3,000,205,000

  • 3,250,000,000

  • 3,025,000,000

View Answer & Explanation
Correct Answer: Option A -

3,205,000,000

Explanation:

Three billion = 3,000,000,000. Two hundred and five million = 205,000,000. Combined: 3,205,000,000.

Write 0.004580.004580.00458 in standard form.

  • 4.58×1034.58 \times 10^34.58×103

  • 4.58×1034.58 \times 10^{-3}4.58×103

  • 4.58×1024.58 \times 10^{-2}4.58×102

  • 45.8×10445.8 \times 10^{-4}45.8×104

View Answer & Explanation
Correct Answer: Option B -

4.58×1034.58 \times 10^{-3}4.58×103

Explanation:

Move the decimal point 3 places to the right to get 4.58. Therefore, the power is -3: 4.58×1034.58 \times 10^{-3}4.58×103.

Express 3.12×1053.12 \times 10^53.12×105 as an ordinary number.

  • 312,000

  • 31,200

  • 3,120,000

  • 312,000,000

View Answer & Explanation
Correct Answer: Option A -

312,000

Explanation:

Move the decimal point 5 places to the right: 3.12 becomes 312,000.

Simplify (2×103)×(4×102)(2 \times 10^3) \times (4 \times 10^2)(2×103)×(4×102) leaving your answer in standard form.

  • 6×1056 \times 10^56×105

  • 8×1068 \times 10^68×106

  • 8×1058 \times 10^58×105

  • 6×1066 \times 10^66×106

View Answer & Explanation
Correct Answer: Option C -

8×1058 \times 10^58×105

Explanation:

Multiply the coefficients: 2×4=82 \times 4 = 82×4=8. Add the indices: 3+2=53 + 2 = 53+2=5. Result: 8×1058 \times 10^58×105.

Which of the following is equivalent to 1 trillion?

  • 10910^9109

  • 101210^{12}1012

  • 101510^{15}1015

  • 10610^6106

View Answer & Explanation
Correct Answer: Option B -

101210^{12}1012

Explanation:

1 million is 10610^6106, 1 billion is 10910^9109, and 1 trillion is 101210^{12}1012.

Correct 5,6925,6925,692 to the nearest thousand.

  • 5,000

  • 5,700

  • 6,000

  • 5,600

View Answer & Explanation
Correct Answer: Option C -

6,000

Explanation:

The hundreds digit is 6 (which is 5\ge 55), so round up the thousands digit from 5 to 6. Result: 6,000.

Express the product of 0.020.020.02 and 0.030.030.03 in standard form.

  • 6×1036 \times 10^{-3}6×103

  • 6×1046 \times 10^{-4}6×104

  • 6×1026 \times 10^{-2}6×102

  • 60×10460 \times 10^{-4}60×104

View Answer & Explanation
Correct Answer: Option B -

6×1046 \times 10^{-4}6×104

Explanation:

0.02×0.03=0.00060.02 \times 0.03 = 0.00060.02×0.03=0.0006. In standard form, this is 6×1046 \times 10^{-4}6×104.

Convert 131013_{10}1310 to a binary number.

  • 110121101_211012

  • 101121011_210112

  • 111021110_211102

  • 100121001_210012

View Answer & Explanation
Correct Answer: Option A -

110121101_211012

Explanation:

Divide 13 by 2 repeatedly: 13/2 = 6 r 1 6/2 = 3 r 0 3/2 = 1 r 1 1/2 = 0 r 1 Reading remainders upwards: 110121101_211012.

Convert 101021010_210102 to a base 10 number.

  • 8

  • 10

  • 12

  • 14

View Answer & Explanation
Correct Answer: Option B -

10

Explanation:

1×23+0×22+1×21+0×20=8+0+2+0=101 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 8 + 0 + 2 + 0 = 101×23+0×22+1×21+0×20=8+0+2+0=10.

More from BECE

Found in Junior Secondary School Certification

BECE Mathematics Statistics & Probability

Practice interpreting data and understanding likelihood, including frequency tables and probability outcomes.

Practice Now

BECE Mathematics Algebraic Processes

Master algebraic components from basic expressions to expansion, factorization, and linear equations.

Practice Now
ExamOven Logo
ExamOven Support
We typically reply instantly